From: Chow Ying Qi (69365) To: Dr. Rosmawati Firstly, I would like to express my grattitude to you which you had paid a lot of effort in giving us the best lectures. I will note down the suggestion and feedbacks you had given us during our PBL sessions, including how to become more confident andContinue reading “Task 11:Self-Reflection on Biochemistry”
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Task 10b: PBL 2 & FILA table
We exchanged information and discuss on what we have found from our PBL trigger.
Task 10a: Glycolysis, Kreb Cycle & Electron Transport System
We filmed a video on the process of Glycolysis, Kreb Cycle & Electron Transport Chain.
Task 9: Self-Reflection On Lipids
~Lee Jie Ying (70148) In this topic, I have learnt that lipids are biomolecules that are soluble in organic solvents. There are two types of lipids that are non-polar lipids and polar lipids. Non-polar lipids are act as energy storage and polar lipids are the basis of bilayers. Lipids are classified into several groups thatContinue reading “Task 9: Self-Reflection On Lipids”
Task 8: Self-Reflection On Carbohydrates
~Lee Jie Ying (70148) Carbohydrates is divided into three types that is monosaccharides, disaccharides and polysaccharides. Monosaccharides are simple sugars, the most common of which is glucose. In monosaccharides, the number of carbons usually ranges from three to seven. Monosaccharides are the simplest carbohydrates and they cannot be hydrolyzed to smaller carbohydrates under mild conditions.Continue reading “Task 8: Self-Reflection On Carbohydrates”
Task 7: Mind map of Vitamins & FILA table for PBL 1
On week 9, our class has carried out our first PBL session. To know more about the facts that we have discussed about, you can download the file below, which is our FILA table. It’s mainly about malnutrition.
Task 6-Michaelis-Menten and Lineweaver Burke plot
Task 5: Differentiate fibrous and globular proteins
Task 4: Solving Henderson-Hasselbach equation
Calculate the pH of a mixture of 0.1 M acetic acid and 0.2 M sodium acetate. (The pKa of acetic is 4.76) Henderson-Hasselbalch equation: solution: CH3COOH ⇌ CH3COO– + H+